1/4(y+12)=3/4(8-y)

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Solution for 1/4(y+12)=3/4(8-y) equation:



1/4(y+12)=3/4(8-y)
We move all terms to the left:
1/4(y+12)-(3/4(8-y))=0
Domain of the equation: 4(y+12)!=0
y∈R
Domain of the equation: 4(8-y))!=0
y∈R
We add all the numbers together, and all the variables
1/4(y+12)-(3/4(-1y+8))=0
We calculate fractions
(4y(-)/(4(y+12)*4(-1y+8)))+(-12yy/(4(y+12)*4(-1y+8)))=0
We calculate terms in parentheses: +(4y(-)/(4(y+12)*4(-1y+8))), so:
4y(-)/(4(y+12)*4(-1y+8))
We add all the numbers together, and all the variables
4y0/(4(y+12)*4(-1y+8))
We multiply all the terms by the denominator
4y0
We add all the numbers together, and all the variables
4y
Back to the equation:
+(4y)
We calculate terms in parentheses: +(-12yy/(4(y+12)*4(-1y+8))), so:
-12yy/(4(y+12)*4(-1y+8))
We multiply all the terms by the denominator
-12yy
Back to the equation:
+(-12yy)
We get rid of parentheses
4y-12yy=0

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