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1/4(x-7)=3/2(x+3)
We move all terms to the left:
1/4(x-7)-(3/2(x+3))=0
Domain of the equation: 4(x-7)!=0
x∈R
Domain of the equation: 2(x+3))!=0We calculate fractions
x∈R
(2xx/(4(x-7)*2(x+3)))+(-12xx/(4(x-7)*2(x+3)))=0
We calculate terms in parentheses: +(2xx/(4(x-7)*2(x+3))), so:
2xx/(4(x-7)*2(x+3))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-12xx/(4(x-7)*2(x+3))), so:We get rid of parentheses
-12xx/(4(x-7)*2(x+3))
We multiply all the terms by the denominator
-12xx
Back to the equation:
+(-12xx)
2xx-12xx=0
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