1/4(x-3)=1/5(x+4)

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Solution for 1/4(x-3)=1/5(x+4) equation: 



1/4(x-3)=1/5(x+4)

We move all terms to the left:

1/4(x-3)-(1/5(x+4))=0



Domain of the equation: 4(x-3)!=0

x∈R





Domain of the equation: 5(x+4))!=0

x∈R



We calculate fractions


(5xx/(4(x-3)*5(x+4)))+(-4xx/(4(x-3)*5(x+4)))=0



We calculate terms in parentheses: +(5xx/(4(x-3)*5(x+4))), so:

5xx/(4(x-3)*5(x+4))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-4xx/(4(x-3)*5(x+4))), so:

-4xx/(4(x-3)*5(x+4))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

5xx-4xx=0

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