1/4(x+8)-2=1/6(x-12)

Solution for 1/4(x+8)-2=1/6(x-12) equation:

1/4(x+8)-2=1/6(x-12)

We move all terms to the left:

1/4(x+8)-2-(1/6(x-12))=0


Domain of the equation: 4(x+8)!=0

x∈R



Domain of the equation: 6(x-12))!=0

x∈R


We calculate fractions


(6xx/(4(x+8)*6(x-12)))+(-4xx/(4(x+8)*6(x-12)))-2=0


We calculate terms in parentheses: +(6xx/(4(x+8)*6(x-12))), so:

6xx/(4(x+8)*6(x-12))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-4xx/(4(x+8)*6(x-12))), so:

-4xx/(4(x+8)*6(x-12))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

6xx-4xx-2=0

We move all terms containing x to the left, all other terms to the right

6xx-4xx=2