1/4(x+4x)+12=1/2(2-x)10

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Solution for 1/4(x+4x)+12=1/2(2-x)10 equation: 



1/4(x+4x)+12=1/2(2-x)10

We move all terms to the left:

1/4(x+4x)+12-(1/2(2-x)10)=0



Domain of the equation: 4(x+4x)!=0

x∈R





Domain of the equation: 2(2-x)10)!=0

x∈R



We add all the numbers together, and all the variables

1/4(+5x)-(1/2(-1x+2)10)+12=0

We calculate fractions


(2x(-)/(4(+5x)*2(-1x+2)10))+(-4x0/(4(+5x)*2(-1x+2)10))+12=0



We calculate terms in parentheses: +(2x(-)/(4(+5x)*2(-1x+2)10)), so:

2x(-)/(4(+5x)*2(-1x+2)10)

We add all the numbers together, and all the variables

2x0/(4(+5x)*2(-1x+2)10)

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-4x0/(4(+5x)*2(-1x+2)10)), so:

-4x0/(4(+5x)*2(-1x+2)10)

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

2x-4x+12=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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