1/4(x+4)=1/6(3x-2)

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Solution for 1/4(x+4)=1/6(3x-2) equation: 



1/4(x+4)=1/6(3x-2)

We move all terms to the left:

1/4(x+4)-(1/6(3x-2))=0



Domain of the equation: 4(x+4)!=0

x∈R





Domain of the equation: 6(3x-2))!=0

x∈R



We calculate fractions


(6x3/(4(x+4)*6(3x-2)))+(-4xx/(4(x+4)*6(3x-2)))=0



We calculate terms in parentheses: +(6x3/(4(x+4)*6(3x-2))), so:

6x3/(4(x+4)*6(3x-2))

We multiply all the terms by the denominator


6x3

We add all the numbers together, and all the variables

6x^3

We do not support expression: x^3

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