1/4(x+4)-1/5x=x

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Solution for 1/4(x+4)-1/5x=x equation: 



1/4(x+4)-1/5x=x

We move all terms to the left:

1/4(x+4)-1/5x-(x)=0



Domain of the equation: 4(x+4)!=0

x∈R





Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/4(x+4)-1/5x=0

We calculate fractions


-1x+5x/(20x^2+80x)+(-4xx/(20x^2+80x)=0



We calculate terms in parentheses: +(-4xx/(20x^2+80x), so:

-4xx/(20x^2+80x

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

-1x+5x/(20x^2+80x)-4xx=0

We multiply all the terms by the denominator


-1x*(20x^2+80x)+5x-4xx*(20x^2+80x)=0

We add all the numbers together, and all the variables

5x-1x*(20x^2+80x)-4xx*(20x^2+80x)=0

We multiply parentheses

-20x^3-80x^2-80x^3-320x^2+5x=0

We do not support expression: x^3

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