1/4(x+3)=2/5(x+6)

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Solution for 1/4(x+3)=2/5(x+6) equation: 



1/4(x+3)=2/5(x+6)

We move all terms to the left:

1/4(x+3)-(2/5(x+6))=0



Domain of the equation: 4(x+3)!=0

x∈R





Domain of the equation: 5(x+6))!=0

x∈R



We calculate fractions


(5xx/(4(x+3)*5(x+6)))+(-8xx/(4(x+3)*5(x+6)))=0



We calculate terms in parentheses: +(5xx/(4(x+3)*5(x+6))), so:

5xx/(4(x+3)*5(x+6))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-8xx/(4(x+3)*5(x+6))), so:

-8xx/(4(x+3)*5(x+6))

We multiply all the terms by the denominator


-8xx

Back to the equation:

+(-8xx)



We get rid of parentheses

5xx-8xx=0

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