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1/4(x+3)+3/4x=13/4
We move all terms to the left:
1/4(x+3)+3/4x-(13/4)=0
Domain of the equation: 4(x+3)!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
1/4(x+3)+3/4x-(+13/4)=0
We get rid of parentheses
1/4(x+3)+3/4x-13/4=0
We calculate fractions
4x/(4(x+3)*4x*4)+(12xx/(4(x+3)*4x*4)=0
We calculate terms in parentheses: +(12xx/(4(x+3)*4x*4), so:We multiply all the terms by the denominator
12xx/(4(x+3)*4x*4
We multiply all the terms by the denominator
12xx
Back to the equation:
+(12xx)
4x+12xx*(4(x+3)*4x*4)=0
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