1/4(x+2)=4/3(x+2)x=

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Solution for 1/4(x+2)=4/3(x+2)x= equation: 



1/4(x+2)=4/3(x+2)x=

We move all terms to the left:

1/4(x+2)-(4/3(x+2)x)=0



Domain of the equation: 4(x+2)!=0

x∈R





Domain of the equation: 3(x+2)x)!=0

x∈R



We calculate fractions


(3xx/(4(x+2)*3(x+2)x))+(-16xx/(4(x+2)*3(x+2)x))=0



We calculate terms in parentheses: +(3xx/(4(x+2)*3(x+2)x)), so:

3xx/(4(x+2)*3(x+2)x)

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-16xx/(4(x+2)*3(x+2)x)), so:

-16xx/(4(x+2)*3(x+2)x)

We multiply all the terms by the denominator


-16xx

Back to the equation:

+(-16xx)



We get rid of parentheses

3xx-16xx=0

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