1/4(u-16)=1/2(6-u)

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Solution for 1/4(u-16)=1/2(6-u) equation: 



1/4(u-16)=1/2(6-u)

We move all terms to the left:

1/4(u-16)-(1/2(6-u))=0



Domain of the equation: 4(u-16)!=0

u∈R





Domain of the equation: 2(6-u))!=0

u∈R



We add all the numbers together, and all the variables

1/4(u-16)-(1/2(-1u+6))=0

We calculate fractions


(2u(-)/(4(u-16)*2(-1u+6)))+(-4uu/(4(u-16)*2(-1u+6)))=0



We calculate terms in parentheses: +(2u(-)/(4(u-16)*2(-1u+6))), so:

2u(-)/(4(u-16)*2(-1u+6))

We add all the numbers together, and all the variables

2u0/(4(u-16)*2(-1u+6))

We multiply all the terms by the denominator


2u0

We add all the numbers together, and all the variables

2u

Back to the equation:

+(2u)





We calculate terms in parentheses: +(-4uu/(4(u-16)*2(-1u+6))), so:

-4uu/(4(u-16)*2(-1u+6))

We multiply all the terms by the denominator


-4uu

Back to the equation:

+(-4uu)



We get rid of parentheses

2u-4uu=0

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