1/4(p+3)=5/6(2p+2)

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Solution for 1/4(p+3)=5/6(2p+2) equation: 



1/4(p+3)=5/6(2p+2)

We move all terms to the left:

1/4(p+3)-(5/6(2p+2))=0



Domain of the equation: 4(p+3)!=0

p∈R





Domain of the equation: 6(2p+2))!=0

p∈R



We calculate fractions


(6p2/(4(p+3)*6(2p+2)))+(-20pp/(4(p+3)*6(2p+2)))=0



We calculate terms in parentheses: +(6p2/(4(p+3)*6(2p+2))), so:

6p2/(4(p+3)*6(2p+2))

We multiply all the terms by the denominator


6p2

We add all the numbers together, and all the variables

6p^2

Back to the equation:

+(6p^2)





We calculate terms in parentheses: +(-20pp/(4(p+3)*6(2p+2))), so:

-20pp/(4(p+3)*6(2p+2))

We multiply all the terms by the denominator


-20pp

Back to the equation:

+(-20pp)



We get rid of parentheses

6p^2-20pp=0

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