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1/4(9-2x)=1/9(3x+4)
We move all terms to the left:
1/4(9-2x)-(1/9(3x+4))=0
Domain of the equation: 4(9-2x)!=0
x∈R
Domain of the equation: 9(3x+4))!=0We add all the numbers together, and all the variables
x∈R
1/4(-2x+9)-(1/9(3x+4))=0
We calculate fractions
(9x3/(4(-2x+9)*9(3x+4)))+(-4x0/(4(-2x+9)*9(3x+4)))=0
We calculate terms in parentheses: +(9x3/(4(-2x+9)*9(3x+4))), so:
9x3/(4(-2x+9)*9(3x+4))
We multiply all the terms by the denominator
9x3
We add all the numbers together, and all the variables
9x^3
We do not support expression: x^3
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