1/4(8y+12)-5=-1/2(2y-8)

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Solution for 1/4(8y+12)-5=-1/2(2y-8) equation: 



1/4(8y+12)-5=-1/2(2y-8)

We move all terms to the left:

1/4(8y+12)-5-(-1/2(2y-8))=0



Domain of the equation: 4(8y+12)!=0

y∈R





Domain of the equation: 2(2y-8))!=0

y∈R



We calculate fractions


(2y2/(4(8y+12)*2(2y-8)))+(-(-4y8)/(4(8y+12)*2(2y-8)))-5=0



We calculate terms in parentheses: +(2y2/(4(8y+12)*2(2y-8))), so:

2y2/(4(8y+12)*2(2y-8))

We multiply all the terms by the denominator


2y2

We add all the numbers together, and all the variables

2y^2

Back to the equation:

+(2y^2)





We calculate terms in parentheses: +(-(-4y8)/(4(8y+12)*2(2y-8))), so:

-(-4y8)/(4(8y+12)*2(2y-8))

We add all the numbers together, and all the variables

-(-4y^8)/(4(8y+12)*2(2y-8))

We multiply all the terms by the denominator


-(-4y^8)

We do not support eypression: y^8

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