1/4(8x-20)+2x-4=3(x+1)+2(x-3)

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Solution for 1/4(8x-20)+2x-4=3(x+1)+2(x-3) equation: 



1/4(8x-20)+2x-4=3(x+1)+2(x-3)

We move all terms to the left:

1/4(8x-20)+2x-4-(3(x+1)+2(x-3))=0



Domain of the equation: 4(8x-20)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/4(8x-20)-(3(x+1)+2(x-3))-4=0

We multiply all the terms by the denominator


2x*4(8x-20)-((3(x+1)+2(x-3)))*4(8x-20)-4*4(8x-20)+1=0



We calculate terms in parentheses: -((3(x+1)+2(x-3)))*4(8x-20), so:

(3(x+1)+2(x-3)))*4(8x-20



Wy multiply elements

8x^2(8-((3(x+1)+2(x-3)))*4(8x-20)-16x(8+1=0

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