1/4(8x-12)=-7x-x+7

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Solution for 1/4(8x-12)=-7x-x+7 equation: 



1/4(8x-12)=-7x-x+7

We move all terms to the left:

1/4(8x-12)-(-7x-x+7)=0



Domain of the equation: 4(8x-12)!=0

x∈R



We add all the numbers together, and all the variables

1/4(8x-12)-(-8x+7)=0

We get rid of parentheses

1/4(8x-12)+8x-7=0

We multiply all the terms by the denominator


8x*4(8x-12)-7*4(8x-12)+1=0

Wy multiply elements

32x^2(8-28x(8+1=0

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