1/4(8x-12)+4x=9-1/2(4x+8x)

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Solution for 1/4(8x-12)+4x=9-1/2(4x+8x) equation:



1/4(8x-12)+4x=9-1/2(4x+8x)
We move all terms to the left:
1/4(8x-12)+4x-(9-1/2(4x+8x))=0
Domain of the equation: 4(8x-12)!=0
x∈R
Domain of the equation: 2(4x+8x))!=0
x∈R
We add all the numbers together, and all the variables
1/4(8x-12)+4x-(9-1/2(+12x))=0
We add all the numbers together, and all the variables
4x+1/4(8x-12)-(9-1/2(+12x))=0
We calculate fractions
4x+(2x(+)/(4(8x-12)*2(+12x)))+(-(-4x8)/(4(8x-12)*2(+12x)))=0
We calculate terms in parentheses: +(2x(+)/(4(8x-12)*2(+12x))), so:
2x(+)/(4(8x-12)*2(+12x))
We add all the numbers together, and all the variables
2x0/(4(8x-12)*2(+12x))
We multiply all the terms by the denominator
2x0
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-(-4x8)/(4(8x-12)*2(+12x))), so:
-(-4x8)/(4(8x-12)*2(+12x))
We add all the numbers together, and all the variables
-(-4x^8)/(4(8x-12)*2(+12x))
We multiply all the terms by the denominator
-(-4x^8)
We do not support expression: x^8

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