1/4(8x+32)-7=-1/3(12x-24)

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Solution for 1/4(8x+32)-7=-1/3(12x-24) equation: 



1/4(8x+32)-7=-1/3(12x-24)

We move all terms to the left:

1/4(8x+32)-7-(-1/3(12x-24))=0



Domain of the equation: 4(8x+32)!=0

x∈R





Domain of the equation: 3(12x-24))!=0

x∈R



We calculate fractions


(3x1/(4(8x+32)*3(12x-24)))+(-(-4x8)/(4(8x+32)*3(12x-24)))-7=0



We calculate terms in parentheses: +(3x1/(4(8x+32)*3(12x-24))), so:

3x1/(4(8x+32)*3(12x-24))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-(-4x8)/(4(8x+32)*3(12x-24))), so:

-(-4x8)/(4(8x+32)*3(12x-24))

We add all the numbers together, and all the variables

-(-4x^8)/(4(8x+32)*3(12x-24))

We multiply all the terms by the denominator


-(-4x^8)

We do not support expression: x^8

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