1/4(8a-20)=1/2(10a-4)

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Solution for 1/4(8a-20)=1/2(10a-4) equation: 



1/4(8a-20)=1/2(10a-4)

We move all terms to the left:

1/4(8a-20)-(1/2(10a-4))=0



Domain of the equation: 4(8a-20)!=0

a∈R





Domain of the equation: 2(10a-4))!=0

a∈R



We calculate fractions


(2a1/(4(8a-20)*2(10a-4)))+(-4a8/(4(8a-20)*2(10a-4)))=0



We calculate terms in parentheses: +(2a1/(4(8a-20)*2(10a-4))), so:

2a1/(4(8a-20)*2(10a-4))

We multiply all the terms by the denominator


2a1

We add all the numbers together, and all the variables

2a

Back to the equation:

+(2a)





We calculate terms in parentheses: +(-4a8/(4(8a-20)*2(10a-4))), so:

-4a8/(4(8a-20)*2(10a-4))

We multiply all the terms by the denominator


-4a8

We add all the numbers together, and all the variables

-4a^8

We do not support eapression: a^8

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