1/4(8-20c)-(5+c)+3(2c-5)

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Solution for 1/4(8-20c)-(5+c)+3(2c-5) equation: 


c in (-oo:+oo)

(1/4)*(8-(20*c))+3*(2*c-5)-c-5 = 0

(1/4)*(8-20*c)+3*(2*c-5)-c-5 = 0

1/4*(8-20*c)+3*(2*c-5)-c-5 = 0

1/4*(8-20*c)+3*(2*c-5)-c-5 = 0

c-c-13-5 = 0

-13-5 = 0

-18 = 0

-18 = 0

c belongs to the empty set

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