1/4(7-c)=2c-41

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Solution for 1/4(7-c)=2c-41 equation: 



1/4(7-c)=2c-41

We move all terms to the left:

1/4(7-c)-(2c-41)=0



Domain of the equation: 4(7-c)!=0

c∈R



We add all the numbers together, and all the variables

1/4(-1c+7)-(2c-41)=0

We get rid of parentheses

1/4(-1c+7)-2c+41=0

We multiply all the terms by the denominator


-2c*4(-1c+7)+41*4(-1c+7)+1=0

Wy multiply elements

-8c^2(-+164c(-+1=0

We use the square of the difference formula

-8c^2(-164c(-1=0

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