1/4(5y+4)=1/3(2y+1)

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Solution for 1/4(5y+4)=1/3(2y+1) equation: 



1/4(5y+4)=1/3(2y+1)

We move all terms to the left:

1/4(5y+4)-(1/3(2y+1))=0



Domain of the equation: 4(5y+4)!=0

y∈R





Domain of the equation: 3(2y+1))!=0

y∈R



We calculate fractions


(3y2/(4(5y+4)*3(2y+1)))+(-4y5/(4(5y+4)*3(2y+1)))=0



We calculate terms in parentheses: +(3y2/(4(5y+4)*3(2y+1))), so:

3y2/(4(5y+4)*3(2y+1))

We multiply all the terms by the denominator


3y2

We add all the numbers together, and all the variables

3y^2

Back to the equation:

+(3y^2)





We calculate terms in parentheses: +(-4y5/(4(5y+4)*3(2y+1))), so:

-4y5/(4(5y+4)*3(2y+1))

We multiply all the terms by the denominator


-4y5

We add all the numbers together, and all the variables

-4y^5

We do not support eypression: y^5

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