1/4(4y+8)-7=-1/9(18y-36)

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Solution for 1/4(4y+8)-7=-1/9(18y-36) equation: 



1/4(4y+8)-7=-1/9(18y-36)

We move all terms to the left:

1/4(4y+8)-7-(-1/9(18y-36))=0



Domain of the equation: 4(4y+8)!=0

y∈R





Domain of the equation: 9(18y-36))!=0

y∈R



We calculate fractions


(9y1/(4(4y+8)*9(18y-36)))+(-(-4y4)/(4(4y+8)*9(18y-36)))-7=0



We calculate terms in parentheses: +(9y1/(4(4y+8)*9(18y-36))), so:

9y1/(4(4y+8)*9(18y-36))

We multiply all the terms by the denominator


9y1

We add all the numbers together, and all the variables

9y

Back to the equation:

+(9y)





We calculate terms in parentheses: +(-(-4y4)/(4(4y+8)*9(18y-36))), so:

-(-4y4)/(4(4y+8)*9(18y-36))

We add all the numbers together, and all the variables

-(-4y^4)/(4(4y+8)*9(18y-36))

We multiply all the terms by the denominator


-(-4y^4)

We do not support eypression: y^4

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