1/4(4x-8)=1/8(16x+12)

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Solution for 1/4(4x-8)=1/8(16x+12) equation: 



1/4(4x-8)=1/8(16x+12)

We move all terms to the left:

1/4(4x-8)-(1/8(16x+12))=0



Domain of the equation: 4(4x-8)!=0

x∈R





Domain of the equation: 8(16x+12))!=0

x∈R



We calculate fractions


(8x1/(4(4x-8)*8(16x+12)))+(-4x4/(4(4x-8)*8(16x+12)))=0



We calculate terms in parentheses: +(8x1/(4(4x-8)*8(16x+12))), so:

8x1/(4(4x-8)*8(16x+12))

We multiply all the terms by the denominator


8x1

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-4x4/(4(4x-8)*8(16x+12))), so:

-4x4/(4(4x-8)*8(16x+12))

We multiply all the terms by the denominator


-4x4

We add all the numbers together, and all the variables

-4x^4

We do not support expression: x^4

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