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1/4(4x+8)-x=3(1-x)+3x
We move all terms to the left:
1/4(4x+8)-x-(3(1-x)+3x)=0
Domain of the equation: 4(4x+8)!=0We add all the numbers together, and all the variables
x∈R
1/4(4x+8)-x-(3(-1x+1)+3x)=0
We add all the numbers together, and all the variables
-1x+1/4(4x+8)-(3(-1x+1)+3x)=0
We multiply all the terms by the denominator
-1x*4(4x+8)-((3(-1x+1)+3x))*4(4x+8)+1=0
We calculate terms in parentheses: -((3(-1x+1)+3x))*4(4x+8), so:Wy multiply elements
(3(-1x+1)+3x))*4(4x+8
-4x^2(4-((3(-1x+1)+3x))*4(4x+8)+1=0
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