1/4(40-8x)=(9x+2-5x

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Solution for 1/4(40-8x)=(9x+2-5x equation:



1/4(40-8x)=(9x+2-5x
We move all terms to the left:
1/4(40-8x)-((9x+2-5x)=0
Domain of the equation: 4(40-8x)!=0
x∈R
We add all the numbers together, and all the variables
1/4(-8x+40)-((4x+2)=0
We multiply all the terms by the denominator
-(((4x+2))*4(-8x+40)+1=0

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