1/4(40-8x)-19x=2-5x

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Solution for 1/4(40-8x)-19x=2-5x equation: 



1/4(40-8x)-19x=2-5x

We move all terms to the left:

1/4(40-8x)-19x-(2-5x)=0



Domain of the equation: 4(40-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-8x+40)-19x-(-5x+2)=0

We add all the numbers together, and all the variables

-19x+1/4(-8x+40)-(-5x+2)=0

We get rid of parentheses

-19x+1/4(-8x+40)+5x-2=0

We multiply all the terms by the denominator


-19x*4(-8x+40)+5x*4(-8x+40)-2*4(-8x+40)+1=0

Wy multiply elements

-76x^2(-+20x^2(--8x(-+1=0

We use the square of the difference formula

-76x^2(-20x^2(+8x(-1=0

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