1/4(40+8x)=19x+2-5x

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Solution for 1/4(40+8x)=19x+2-5x equation:



1/4(40+8x)=19x+2-5x
We move all terms to the left:
1/4(40+8x)-(19x+2-5x)=0
Domain of the equation: 4(40+8x)!=0
x∈R
We add all the numbers together, and all the variables
1/4(8x+40)-(14x+2)=0
We get rid of parentheses
1/4(8x+40)-14x-2=0
We multiply all the terms by the denominator
-14x*4(8x+40)-2*4(8x+40)+1=0
Wy multiply elements
-56x^2(8-8x(8+1=0

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