1/4(3x-8+9x)=2x-4+x

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Solution for 1/4(3x-8+9x)=2x-4+x equation: 



1/4(3x-8+9x)=2x-4+x

We move all terms to the left:

1/4(3x-8+9x)-(2x-4+x)=0



Domain of the equation: 4(3x-8+9x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(12x-8)-(3x-4)=0

We get rid of parentheses

1/4(12x-8)-3x+4=0

We multiply all the terms by the denominator


-3x*4(12x-8)+4*4(12x-8)+1=0

Wy multiply elements

-12x^2(1+16x(1+1=0

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