1/4(3x-2)-1/3(2x+3)=2/3-x

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Solution for 1/4(3x-2)-1/3(2x+3)=2/3-x equation: 



1/4(3x-2)-1/3(2x+3)=2/3-x

We move all terms to the left:

1/4(3x-2)-1/3(2x+3)-(2/3-x)=0



Domain of the equation: 4(3x-2)!=0

x∈R





Domain of the equation: 3(2x+3)!=0

x∈R





Domain of the equation: 3-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

1/4(3x-2)-1/3(2x+3)-(-1x+2/3)=0

We get rid of parentheses

1/4(3x-2)-1/3(2x+3)+1x-2/3=0

We calculate fractions


1x+(9x2/(4(3x-2)*3(2x+3)*3)+(-4x3/(4(3x-2)*3(2x+3)*3)+(-8x3/(4(3x-2)*3(2x+3)*3)=0



We calculate terms in parentheses: +(9x2/(4(3x-2)*3(2x+3)*3)+(-4x3/(4(3x-2)*3(2x+3)*3)+(-8x3/(4(3x-2)*3(2x+3)*3), so:

9x2/(4(3x-2)*3(2x+3)*3)+(-4x3/(4(3x-2)*3(2x+3)*3)+(-8x3/(4(3x-2)*3(2x+3)*3

We can not solve this equation

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