1/4(32x+28)-3x=18x-5(3x+7)

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Solution for 1/4(32x+28)-3x=18x-5(3x+7) equation: 



1/4(32x+28)-3x=18x-5(3x+7)

We move all terms to the left:

1/4(32x+28)-3x-(18x-5(3x+7))=0



Domain of the equation: 4(32x+28)!=0

x∈R



We add all the numbers together, and all the variables

-3x+1/4(32x+28)-(18x-5(3x+7))=0

We multiply all the terms by the denominator


-3x*4(32x+28)-((18x-5(3x+7)))*4(32x+28)+1=0



We calculate terms in parentheses: -((18x-5(3x+7)))*4(32x+28), so:

(18x-5(3x+7)))*4(32x+28



Wy multiply elements

-12x^2(3-((18x-5(3x+7)))*4(32x+28)+1=0

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