1/4(2x-28)=10

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Solution for 1/4(2x-28)=10 equation: 



1/4(2x-28)=10

We move all terms to the left:

1/4(2x-28)-(10)=0



Domain of the equation: 4(2x-28)!=0

x∈R



We multiply all the terms by the denominator


-10*4(2x-28)+1=0

Wy multiply elements

-40x(2+1=0

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