1/4(2m+3)=1/5(m-2)

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Solution for 1/4(2m+3)=1/5(m-2) equation: 



1/4(2m+3)=1/5(m-2)

We move all terms to the left:

1/4(2m+3)-(1/5(m-2))=0



Domain of the equation: 4(2m+3)!=0

m∈R





Domain of the equation: 5(m-2))!=0

m∈R



We calculate fractions


(5mm/(4(2m+3)*5(m-2)))+(-4m2/(4(2m+3)*5(m-2)))=0



We calculate terms in parentheses: +(5mm/(4(2m+3)*5(m-2))), so:

5mm/(4(2m+3)*5(m-2))

We multiply all the terms by the denominator


5mm

Back to the equation:

+(5mm)





We calculate terms in parentheses: +(-4m2/(4(2m+3)*5(m-2))), so:

-4m2/(4(2m+3)*5(m-2))

We multiply all the terms by the denominator


-4m2

We add all the numbers together, and all the variables

-4m^2

Back to the equation:

+(-4m^2)



We get rid of parentheses

-4m^2+5mm=0

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