1/4(20x-12)=1/3(9x-27)

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Solution for 1/4(20x-12)=1/3(9x-27) equation: 



1/4(20x-12)=1/3(9x-27)

We move all terms to the left:

1/4(20x-12)-(1/3(9x-27))=0



Domain of the equation: 4(20x-12)!=0

x∈R





Domain of the equation: 3(9x-27))!=0

x∈R



We calculate fractions


(3x9/(4(20x-12)*3(9x-27)))+(-4x2/(4(20x-12)*3(9x-27)))=0



We calculate terms in parentheses: +(3x9/(4(20x-12)*3(9x-27))), so:

3x9/(4(20x-12)*3(9x-27))

We multiply all the terms by the denominator


3x9

We add all the numbers together, and all the variables

3x^9

We do not support expression: x^9

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