1/4(20-b)=6-b

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Solution for 1/4(20-b)=6-b equation: 



1/4(20-b)=6-b

We move all terms to the left:

1/4(20-b)-(6-b)=0



Domain of the equation: 4(20-b)!=0

b∈R



We add all the numbers together, and all the variables

1/4(-1b+20)-(-1b+6)=0

We get rid of parentheses

1/4(-1b+20)+1b-6=0

We multiply all the terms by the denominator


1b*4(-1b+20)-6*4(-1b+20)+1=0

Wy multiply elements

4b^2(--24b(-+1=0

We use the square of the difference formula

4b^2(+24b(-1=0

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