If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/4(20-4p)=6-p
We move all terms to the left:
1/4(20-4p)-(6-p)=0
Domain of the equation: 4(20-4p)!=0We add all the numbers together, and all the variables
p∈R
1/4(-4p+20)-(-1p+6)=0
We get rid of parentheses
1/4(-4p+20)+1p-6=0
We multiply all the terms by the denominator
1p*4(-4p+20)-6*4(-4p+20)+1=0
Wy multiply elements
4p^2(--24p(-+1=0
We use the square of the difference formula
4p^2(+24p(-1=0
| -5x-7x-100=140 | | Y=23-4x5 | | 10^b=1,000 | | (y+1)(3y-1)=-10 | | 63+(x+13)=3x | | 7x+39=-10 | | (y+1)(3y-1)=666 | | (y+1)(3y-1)=0 | | 6x-1=-3x+17 | | 1/2x+1=-2x+11 | | 4x+8=32-8 | | 1h^2-2h-2=0 | | 4a+8=14-6+4 | | x+(4x+18)=-7 | | 2a-4/3a+4=0 | | 3x-(23-4x)=12 | | -4x+-6x+2=18 | | 4y-1.9=16.3 | | 2a-4/3a+4=a | | 6.2x=37.2 | | 2a-4/3a+4=10 | | 3-(n×4)=8 | | 2a-4/3a+4=1 | | 3-n×4=8 | | 2(2x+4)=28x | | 4x(4x)+43=7 | | a1=32 | | −x2+36x−62=0 | | 15+t=t+3 | | -4(2x-3)=8x-4 | | 7x-3=3(2x+3) | | k^2+12k-288=0 |