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1/4(2-x)=5+3x
We move all terms to the left:
1/4(2-x)-(5+3x)=0
Domain of the equation: 4(2-x)!=0We add all the numbers together, and all the variables
x∈R
1/4(-1x+2)-(3x+5)=0
We get rid of parentheses
1/4(-1x+2)-3x-5=0
We multiply all the terms by the denominator
-3x*4(-1x+2)-5*4(-1x+2)+1=0
Wy multiply elements
-12x^2(--20x(-+1=0
We use the square of the difference formula
-12x^2(+20x(-1=0
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