1/4(16x-12)=1/8(16x-72)

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Solution for 1/4(16x-12)=1/8(16x-72) equation: 



1/4(16x-12)=1/8(16x-72)

We move all terms to the left:

1/4(16x-12)-(1/8(16x-72))=0



Domain of the equation: 4(16x-12)!=0

x∈R





Domain of the equation: 8(16x-72))!=0

x∈R



We calculate fractions


(8x1/(4(16x-12)*8(16x-72)))+(-4x1/(4(16x-12)*8(16x-72)))=0



We calculate terms in parentheses: +(8x1/(4(16x-12)*8(16x-72))), so:

8x1/(4(16x-12)*8(16x-72))

We multiply all the terms by the denominator


8x1

We add all the numbers together, and all the variables

8x

Back to the equation:

+(8x)





We calculate terms in parentheses: +(-4x1/(4(16x-12)*8(16x-72))), so:

-4x1/(4(16x-12)*8(16x-72))

We multiply all the terms by the denominator


-4x1

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)



We get rid of parentheses

8x-4x=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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