1/4(12x-20)=5x-(2x+1)

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Solution for 1/4(12x-20)=5x-(2x+1) equation:



1/4(12x-20)=5x-(2x+1)
We move all terms to the left:
1/4(12x-20)-(5x-(2x+1))=0
Domain of the equation: 4(12x-20)!=0
x∈R
We multiply all the terms by the denominator
-((5x-(2x+1)))*4(12x-20)+1=0
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20
We calculate terms in parentheses: -((5x-(2x+1)))*4(12x-20), so:
(5x-(2x+1)))*4(12x-20

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