1/4(12x-16)=1/2(8-2x)

Solution for 1/4(12x-16)=1/2(8-2x) equation:

1/4(12x-16)=1/2(8-2x)

We move all terms to the left:

1/4(12x-16)-(1/2(8-2x))=0


Domain of the equation: 4(12x-16)!=0

x∈R



Domain of the equation: 2(8-2x))!=0

x∈R


We add all the numbers together, and all the variables

1/4(12x-16)-(1/2(-2x+8))=0

We calculate fractions


(2x(-)/(4(12x-16)*2(-2x+8)))+(-4x1/(4(12x-16)*2(-2x+8)))=0


We calculate terms in parentheses: +(2x(-)/(4(12x-16)*2(-2x+8))), so:

2x(-)/(4(12x-16)*2(-2x+8))

We add all the numbers together, and all the variables

2x0/(4(12x-16)*2(-2x+8))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)



We calculate terms in parentheses: +(-4x1/(4(12x-16)*2(-2x+8))), so:

-4x1/(4(12x-16)*2(-2x+8))

We multiply all the terms by the denominator


-4x1

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)


We get rid of parentheses

2x-4x=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0