1/4(12x+16)-5x=1/2(-8x+20)

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Solution for 1/4(12x+16)-5x=1/2(-8x+20) equation:



1/4(12x+16)-5x=1/2(-8x+20)
We move all terms to the left:
1/4(12x+16)-5x-(1/2(-8x+20))=0
Domain of the equation: 4(12x+16)!=0
x∈R
Domain of the equation: 2(-8x+20))!=0
x∈R
We add all the numbers together, and all the variables
-5x+1/4(12x+16)-(1/2(-8x+20))=0
We calculate fractions
-5x+(2x(-)/(4(12x+16)*2(-8x+20)))+(-4x1/(4(12x+16)*2(-8x+20)))=0
We calculate terms in parentheses: +(2x(-)/(4(12x+16)*2(-8x+20))), so:
2x(-)/(4(12x+16)*2(-8x+20))
We add all the numbers together, and all the variables
2x0/(4(12x+16)*2(-8x+20))
We multiply all the terms by the denominator
2x0
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-4x1/(4(12x+16)*2(-8x+20))), so:
-4x1/(4(12x+16)*2(-8x+20))
We multiply all the terms by the denominator
-4x1
We add all the numbers together, and all the variables
-4x
Back to the equation:
+(-4x)
We add all the numbers together, and all the variables
-3x+(-4x)=0
We get rid of parentheses
-3x-4x=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0

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