1/4(12-8x)=4((-2x)-6)

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Solution for 1/4(12-8x)=4((-2x)-6) equation: 



1/4(12-8x)=4((-2x)-6)

We move all terms to the left:

1/4(12-8x)-(4((-2x)-6))=0



Domain of the equation: 4(12-8x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(-8x+12)-(4((-2x)-6))=0

We multiply all the terms by the denominator


-((4((-2x)-6)))*4(-8x+12)+1=0



We calculate terms in parentheses: -((4((-2x)-6)))*4(-8x+12), so:

(4((-2x)-6)))*4(-8x+12

We add all the numbers together, and all the variables

-8x+(4((-2x)-6)))*4(+12

Back to the equation:

-(-8x+(4((-2x)-6)))*4(+12)



We add all the numbers together, and all the variables

-(-8x+(4((-2x)-6)))*412+1=0

We move all terms containing x to the left, all other terms to the right

-(-8x+(4((-2x)-6)))*412=-1

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