1/4(12-56x)+3=6+1/2(10-28x)

Solution for 1/4(12-56x)+3=6+1/2(10-28x) equation:

1/4(12-56x)+3=6+1/2(10-28x)

We move all terms to the left:

1/4(12-56x)+3-(6+1/2(10-28x))=0


Domain of the equation: 4(12-56x)!=0

x∈R



Domain of the equation: 2(10-28x))!=0

x∈R


We add all the numbers together, and all the variables

1/4(-56x+12)-(6+1/2(-28x+10))+3=0

We calculate fractions


(2x(-)/(4(-56x+12)*2(-28x+10)))+(-4x0/(4(-56x+12)*2(-28x+10)))+3=0


We calculate terms in parentheses: +(2x(-)/(4(-56x+12)*2(-28x+10))), so:

2x(-)/(4(-56x+12)*2(-28x+10))

We add all the numbers together, and all the variables

2x0/(4(-56x+12)*2(-28x+10))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)



We calculate terms in parentheses: +(-4x0/(4(-56x+12)*2(-28x+10))), so:

-4x0/(4(-56x+12)*2(-28x+10))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)


We get rid of parentheses

2x-4x+3=0

We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2