1/4(12+x)=x-3

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Solution for 1/4(12+x)=x-3 equation: 



1/4(12+x)=x-3

We move all terms to the left:

1/4(12+x)-(x-3)=0



Domain of the equation: 4(12+x)!=0

x∈R



We add all the numbers together, and all the variables

1/4(x+12)-(x-3)=0

We get rid of parentheses

1/4(x+12)-x+3=0

We multiply all the terms by the denominator


-x*4(x+12)+3*4(x+12)+1=0

Wy multiply elements

-4x^2(x+12x(x+1=0

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