1/4(-8q-8)=-10-q

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Solution for 1/4(-8q-8)=-10-q equation: 



1/4(-8q-8)=-10-q

We move all terms to the left:

1/4(-8q-8)-(-10-q)=0



Domain of the equation: 4(-8q-8)!=0

q∈R



We add all the numbers together, and all the variables

1/4(-8q-8)-(-1q-10)=0

We get rid of parentheses

1/4(-8q-8)+1q+10=0

We multiply all the terms by the denominator


1q*4(-8q-8)+10*4(-8q-8)+1=0

Wy multiply elements

4q^2(-+40q(-+1=0

We use the square of the difference formula

4q^2(-40q(-1=0

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