1/3z+2=5

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Solution for 1/3z+2=5 equation: 



1/3z+2=5

We move all terms to the left:

1/3z+2-(5)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R



We add all the numbers together, and all the variables

1/3z-3=0

We multiply all the terms by the denominator


-3*3z+1=0

Wy multiply elements

-9z+1=0

We move all terms containing z to the left, all other terms to the right

-9z=-1

z=-1/-9

z=1/9

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