1/3y+8=12

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Solution for 1/3y+8=12 equation: 



1/3y+8=12

We move all terms to the left:

1/3y+8-(12)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

1/3y-4=0

We multiply all the terms by the denominator


-4*3y+1=0

Wy multiply elements

-12y+1=0

We move all terms containing y to the left, all other terms to the right

-12y=-1

y=-1/-12

y=1/12

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