1/3y+7=1/10y.

Solution for 1/3y+7=1/10y. equation:

1/3y+7=1/10y.

We move all terms to the left:

1/3y+7-(1/10y.)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 10y.)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/3y-(+1/10y.)+7=0

We get rid of parentheses

1/3y-1/10y.+7=0

We calculate fractions


10y/30y^2+(-3y)/30y^2+7=0

We multiply all the terms by the denominator


10y+(-3y)+7*30y^2=0

Wy multiply elements

210y^2+10y+(-3y)=0

We get rid of parentheses

210y^2+10y-3y=0

We add all the numbers together, and all the variables

210y^2+7y=0

a = 210; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·210·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*210}=\frac{-14}{420}
=-1/30
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*210}=\frac{0}{420}
=0
$