1/3y+3=1/2y

Solution for 1/3y+3=1/2y equation:

1/3y+3=1/2y

We move all terms to the left:

1/3y+3-(1/2y)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/3y-(+1/2y)+3=0

We get rid of parentheses

1/3y-1/2y+3=0

We calculate fractions


2y/6y^2+(-3y)/6y^2+3=0

We multiply all the terms by the denominator


2y+(-3y)+3*6y^2=0

Wy multiply elements

18y^2+2y+(-3y)=0

We get rid of parentheses

18y^2+2y-3y=0

We add all the numbers together, and all the variables

18y^2-1y=0

a = 18; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·18·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*18}=\frac{0}{36}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*18}=\frac{2}{36}
=1/18
$