1/3y+10=1/6y

Solution for 1/3y+10=1/6y equation:

1/3y+10=1/6y

We move all terms to the left:

1/3y+10-(1/6y)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 6y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

1/3y-(+1/6y)+10=0

We get rid of parentheses

1/3y-1/6y+10=0

We calculate fractions


6y/18y^2+(-3y)/18y^2+10=0

We multiply all the terms by the denominator


6y+(-3y)+10*18y^2=0

Wy multiply elements

180y^2+6y+(-3y)=0

We get rid of parentheses

180y^2+6y-3y=0

We add all the numbers together, and all the variables

180y^2+3y=0

a = 180; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·180·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*180}=\frac{-6}{360}
=-1/60
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*180}=\frac{0}{360}
=0
$